Find identical capacitor plates- each of area A- are arranged such that adjacent plates are a distance -d- apart- the plates are connected to a of emf V as shown in figure- The charge on plate 1 is - and that on plate 4 is -

Question

Toppr Admin · Accepted Answer

We have capacitance-C-x3B5-oAd and C-QV-x27F9-Q-CVHence- charge on Plate 1 is-xA0-C-x3F5-oAdVand charge on Plate 4 is-xA0-C-x2212-2-x3F5-oAdV

$(A) Charge on plate 1$	$(P) \frac{- ε_{0} A E}{d}$
$(B) Charge on plate 4$	$(Q) \frac{+ ε_{0} A E}{d}$
$(C) Potential difference between plates 1 and 2$	$(R) Zero$
$(D) Potential difference between plates 1 and 5$	$(S) E$

Find identical capacitor plates, each of area $A$ , are arranged such that adjacent plates are at a distance $^{'} d^{'}$ apart, the plates are connected to a source of emf $V$ as shown in figure. The charge on plate 1 is and that on plate 4 is .

We have capacitance,
$C = ε_{o} \frac{A}{d}$ and $C = \frac{Q}{V}$
$⟹ Q = C V$
Hence, charge on Plate 1 is $C = \frac{ϵ_{o} A}{d} V$
and charge on Plate 4 is $C = - \frac{2 ϵ_{o} A}{d} V$

Find identical capacitor plates, each of area A, are arranged such that adjacent plates are at a distance ′d′ apart, the plates are connected to a source of emf V as shown in figure. The charge on plate 1 is ____________ and that on plate 4 is ____________.

We have capacitance,C=εoAd and C=QV⟹Q=CVHence, charge on Plate 1 is C=ϵoAdVand charge on Plate 4 is C=−2ϵoAdV

Find identical capacitor plates, each of area $A$ , are arranged such that adjacent plates are at a distance $^{'} d^{'}$ apart, the plates are connected to a source of emf $V$ as shown in figure. The charge on plate 1 is and that on plate 4 is .

We have capacitance,
$C = ε_{o} \frac{A}{d}$ and $C = \frac{Q}{V}$
$⟹ Q = C V$
Hence, charge on Plate 1 is $C = \frac{ϵ_{o} A}{d} V$
and charge on Plate 4 is $C = - \frac{2 ϵ_{o} A}{d} V$