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Standard IX
Mathematics
Algebraic Identities
Question
Find :
(
3
2
x
+
1
)
3
Open in App
Solution
Verified by Toppr
(
3
x
2
+
1
)
3
is of the form
(
a
+
b
)
3
=
a
3
+
b
3
+
3
a
b
(
a
+
b
)
where
a
=
3
x
2
,
b
=
1
⇒
(
3
x
2
+
1
)
3
=
(
3
x
2
)
3
+
1
3
+
3
×
3
x
2
×
1
(
3
x
2
+
1
)
=
27
x
3
8
+
1
+
3
x
(
3
x
2
+
1
)
=
27
x
3
8
+
1
+
9
x
2
2
+
3
x
=
27
x
3
8
+
9
x
2
2
+
3
x
+
1
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