Given, m−m−12=1−m−33.
⟹ 2m−(m−1)2=3−(m−3)3 ...[Taking LCM of the denominators]
⟹ 2m−m+12=3−m+33 ...{By distribution property]
⟹ m+12=6−m3 ...[On simplifying]
⟹ 3(m+1)=2(6−m) …[Cross-multiplying the denominators]
⟹ 3m+3=12−2m ...{By distribution property]
⟹ 3m+2m=12−3 ...[Transposing x terms to one side]
⟹ 5m=9
⟹ m=95.