Question

Find number of $p\pi -d\pi$ bonds in:
a) Disulphate b) Triphosphate c) Trimetaphosphate
d) Trimer of ${SO}_3$ e) $P_4{O}_{10}$ f) $P_4{O}_6$

Answer 1

(a) Disulphate (Refer to Image 1) $\Rightarrow P\pi -d\pi$ bonds= $4$

(b) Triphosphate (Refer to Image 2) $\Rightarrow P\pi -d\pi$ bonds=$3$

(c) Trimetaphosphate (Refer to Image 3) $\Rightarrow P\pi -d\pi$ bonds=$3$

(d) Trimer of $S{O}_3$ (Refer to Image 4) $\Rightarrow P\pi -d\pi$ bonds=$6$

(e) $P_4{O}_{10}$ (Refer to Image 5) $\Rightarrow P\pi -d\pi$ bonds =$4$

(f) $P_4{O}_6$ (Refer to Image 6) $\Rightarrow P\pi -d\pi$ bonds=$0$

$P\pi -d\pi$ overlaps forms doubel bonds.