Find out the value of K-C each of the following equilibrium respectively from the value of K-P-i- 2NOCl-g-rightleftharpoons 2NO-g-Cl-2-g- K-P-1-8times 10-2- 500 K-ii- CaCO-3-s-rightleftharpoons CaO-s-CO-2-g- K-P-167 1073 K4-4times 10-4- - 1-908-8times 10-4- - 3-88-8times 19-4 - 3-84-4times 10-4 - 1-90

Question

Toppr Admin · Accepted Answer

The relationship between Kp and Kc is Kp-Kc-RT-x394-n-

Find out the value of KC for each of the following equilibrium respectively from the value of KP.(i) 2NOCl(g)⇌2NO(g)+Cl2(g);KP=1.8×10−2 at 500 K(ii) CaCO3(s)⇌CaO(s)+CO2(g);KP=167 at 1073 K4.4×10−4 & 1.908.8×10−4 & 3.88.8×194 & 3.84.4×104 & 1.90

The relationship between Kp and Kc is Kp=Kc(RT)Δn.

The relationship between $K_{p}$ and $K_{c}$ is $K_{p} = K_{c} (R T)^{Δ n}$ .