Find the area and the perimeter of the trapezium shown above-

Question

Toppr Admin · Accepted Answer

REF-ImageArea-xA0- -12 -sum of parallel sides- -xD7- distance between them-xA0- -xA0- -xA0- -xA0- -xA0- -12-xD7-4-5-xD7-2-5-11-25dm2Perimeter - 4-2-5-3-5-14-5dm

Find the area and the perimeter of the trapezium shown above.

REF.Image
Area $= \frac{1}{2}$ (sum of parallel sides) $\times$ distance between them

$= \frac{1}{2} \times (4 + 5) \times 2.5 = 11.25 d m^{2}$

Perimeter = $4 + 2.5 + 3 + 5 = 14.5 d m$

Find the area and the perimeter of the trapezium shown above.

REF.ImageArea =12 (sum of parallel sides) × distance between them =12×(4+5)×2.5=11.25dm2Perimeter = 4+2.5+3+5=14.5dm

REF.Image
Area $= \frac{1}{2}$ (sum of parallel sides) $\times$ distance between them

$= \frac{1}{2} \times (4 + 5) \times 2.5 = 11.25 d m^{2}$

Perimeter = $4 + 2.5 + 3 + 5 = 14.5 d m$