Find the area of a quadrilateral one of whose diagonals is $30$ cm long and the perpendiculars from the two other vertices on this diagonal are $19$ cm and $11$ cm respectively.

Question

Find the area of a quadrilateral one of whose diagonals is 25 cm long and the lengths of perpendiculars from the other two vertices are 16-4 cm and 11-6 cm respectively-

Toppr Admin · Accepted Answer

Area-12-xD7-one diagonal-xD7-Sum of the lengths of the perpendiculars drawn from it on the remaining two vertices-12-xD7-25-xD7-16-4-11-6-252-xD7-28-25-xD7-14-350sq-cm

Find the area of a quadrilateral one of whose diagonals is 25 cm long and the lengths of perpendiculars from the other two vertices are 16.4 cm and 11.6 cm respectively.

Area $= \frac{1}{2} \times$ one diagonal $\times$ Sum of the lengths of the perpendiculars drawn from it on the remaining two vertices.
$= \frac{1}{2} \times 25 \times (16.4 + 11.6)$
$= \frac{25}{2} \times 28 = 25 \times 14 = 350$ sq.cm

Find the area of a quadrilateral one of whose diagonals is 25 cm long and the lengths of perpendiculars from the other two vertices are 16.4 cm and 11.6 cm respectively.

Area=12×one diagonal×Sum of the lengths of the perpendiculars drawn from it on the remaining two vertices.=12×25×(16.4+11.6)=252×28=25×14=350sq.cm

Area $= \frac{1}{2} \times$ one diagonal $\times$ Sum of the lengths of the perpendiculars drawn from it on the remaining two vertices.
$= \frac{1}{2} \times 25 \times (16.4 + 11.6)$
$= \frac{25}{2} \times 28 = 25 \times 14 = 350$ sq.cm