Question

Find the area of shaded region.

Answer 1

Area of the semicircle with AB as diameter
$=\frac{\pi r^2}{2}=\frac{1}{2}\frac{22}{7}(\frac{10\sqrt{2}}{2}{)}^2=\frac{11}{7}\frac{200}{4}=78.57c{m}^2....(1)$
Area of $\Delta le=\frac{1}{2}AB\times LP=\frac{1}{2}\times 10\sqrt{2}\times 5\sqrt{2}=10\times 5=50c{m}^2$
Area of shaded region
$=78.57-50=28.57c{m}^2$