Question

Find the area of the equilateral ABCD. Here, AC$$=22$$cm, BM$$=3$$cm, DN$$=3$$cm and BM$$\perp$$AC, DN$$\perp$$AC.

Answer 1

Here, AC$$=22$$cm, BM$$=3$$cm, DN$$=3$$cm
Area of quadrilateral ABCDF$$=$$Area of $$\Delta$$ABC$$+$$Area of $$\Delta$$ADC
$$=\dfrac{1}{2}\times AC\times BM+\dfrac{1}{2}\times AC\times DN$$
$$=\dfrac{1}{2}\times 22\times 3+\dfrac{1}{2}\times 22\times 3$$
$$=3\times 11+3\times 11$$
$$=33+33$$
$$=66cm^2$$
Thus, the area of quadrilateral ABCD is $$cm^2$$.