Let potential of $$A$$ is zero and that of $$b$$ is $$V$$. Applying charge conservation on given circuit. $$1(V-10)+2(V-0+5(V-10)=10$$ $$8V-60=0$$ $$V=\dfrac{60}{8}=7.5volt$$ So charge in $$2\mu F=2\times 7.5=15\mu C$$
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