Find the complement of the following angle: $$60^\circ$$.
We know, two angles are said to be complementary, if the sum of their measures is $$90^\circ.$$
The given angle is $$60^\circ$$
Let the measure of its complement be $$x^\circ.$$
Then,
$$ \implies x + 60^o = 90^o$$
$$ \implies x = 90^o - 60^o$$
$$ \implies x = 30^\circ$$.
Hence, the complement of the given angle measures $$30^\circ$$.