0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

Find the coordinates of the focus, axis of the parabola ,the equation of directrix and the length of the latus reactum for x 2=6y

Solution
Verified by Toppr

The given equation is x2=6y
Here the coefficient of y is positive.
Hence the parabola opens upwards
On comparing this equation with x2=4ay,
4a=6
a=32
Coordinates of the focus =(0,a)=(0,32)
Since the given equation involves x2, the axis of the parabola is the y-axis
Equation of directrix y=a i.e. y=32
Length of latus rectum =4a=6

Was this answer helpful?
0
Similar Questions
Q1
Find the coordinates of the focus, axis of the parabola ,the equation of directrix and the length of the latus reactum for x 2=6y
View Solution
Q2
For the given parabola find the coordinates of focus, axis, the equation of the directrix and the length of the latus rectum.
x2=6y
View Solution
Q3

Find the coordinates of the focus, axis of the parabola, the equation of directrix and the length of the latus rectum for y2 = – 8x

View Solution
Q4

Find the coordinates of the focus, axis of the parabola, the equation of directrix and the length of the latus rectum for x2 = 6y

View Solution
Q5
Find the coordinates of the focus, axis of the parabola, the equation of directrix and the length of the latus rectum for x2=16y.
View Solution