Find the coordinates of the points where the circle x-2-y-2-4x-4y-5-0 intersects the y-axis-

Question

Toppr Admin · Accepted Answer

On the y-axis- x-0-Putting x-0 in the equation of circle- we get-y2-x2212-4y-x2212-5-0-y-1-y-x2212-5-0y-x2212-1 or y-5Coordinates on the y-axis -0-x2212-1- and -0-5-

Find the coordinates of the points where the circle $x^{2} + y^{2} + 4 x - 4 y - 5 = 0$ intersects the y-axis.

On the y-axis, $x = 0$ .
Putting $x = 0$ in the equation of circle, we get,
$y^{2} - 4 y - 5 = 0$
$(y + 1) (y - 5) = 0$
$y = - 1$ or $y = 5$
Coordinates on the y-axis :
$(0, - 1)$ and $(0, 5)$

Find the coordinates of the points where the circle x2+y2+4x−4y−5=0 intersects the y-axis.

On the y-axis, x=0.Putting x=0 in the equation of circle, we get,y2−4y−5=0(y+1)(y−5)=0y=−1 or y=5Coordinates on the y-axis :(0,−1) and (0,5)

Find the coordinates of the points where the circle $x^{2} + y^{2} + 4 x - 4 y - 5 = 0$ intersects the y-axis.

On the y-axis, $x = 0$ .
Putting $x = 0$ in the equation of circle, we get,
$y^{2} - 4 y - 5 = 0$
$(y + 1) (y - 5) = 0$
$y = - 1$ or $y = 5$
Coordinates on the y-axis :
$(0, - 1)$ and $(0, 5)$