Find the correct option such that the formation of $3$ numbers, using three digit number $128$ ? (Without repeating the numbers)
$281, 221$ and $182$
$281, 851$ and $182$
$681, 821$ and $182$
$281, 821$ and $182$

Question

Find the correct option such that the formation of 3 numbers- using three digit number 128- -Without repeating the numbers-281- 221 and 182281- 851 and 182681- 821 and 182281- 821 and 182

Toppr Admin · Accepted Answer

128 can be written using the general form abc-100-xD7-a-10-xD7-b-cBy changing the alphabetic orders of a-b-c- we get 3 more numbers from 3 digit number-Here- 281-821 and 182 are formed from the 3 digit number 128-

Find the correct option such that the formation of 3 numbers, using three digit number 128? (Without repeating the numbers)281,221 and 182281,851 and 182681,821 and 182281,821 and 182

128 can be written using the general form abc=100×a+10×b+cBy changing the alphabetic orders of a,b,c, we get 3 more numbers from 3 digit number.Here, 281,821 and 182 are formed from the 3 digit number 128.

Find the correct option such that the formation of $3$ numbers, using three digit number $128$ ? (Without repeating the numbers)
$281, 221$ and $182$
$281, 851$ and $182$
$681, 821$ and $182$
$281, 821$ and $182$

$128$ can be written using the general form $a b c = 100 \times a + 10 \times b + c$
By changing the alphabetic orders of $a, b, c$ , we get $3$ more numbers from $3$ digit number.
Here, $281, 821$ and $182$ are formed from the $3$ digit number $128$ .