Find the correct option such that the formation of $3$ numbers, using three digit number $128$? (Without repeating the numbers)

A

$281,221$ and $182$

B

$281,851$ and $182$

C

$681,821$ and $182$

D

$281,821$ and $182$

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Solution

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Correct option is

D

$281,821$ and $182$

$128$ can be written using the general form $abc=100×a+10×b+c$ By changing the alphabetic orders of $a,b,c$, we get $3$ more numbers from $3$ digit number. Here, $281,821$ and $182$ are formed from the $3$ digit number $128$.