Question

Find the cost of polishing a circular table-top of diameter $$1.6$$m, if the rate of polishing is Rs. $$15/m^2$$. (Take $$\pi =3.14$$)

Answer 1

Diameter of the circular table top$$=1.6$$m

$$\therefore$$ Radius of the circular table top$$=\dfrac{1.6}{2}=0.8$$m

Area of circular table top$$=\pi r^2$$

$$=3.14\times 0.8\times 0.8=2.0096m^2$$

Now cost of $$1m^2$$ polishing $$=$$Rs. $$15$$

Then cost of $$2.0096$$ $$m^2$$ polishing $$=15\times 2.0096=$$Rs. $$30.14$$(approx.)

Thus, the cost of polishing a circular table top is Rs. $$30.14$$(approx.)