Find the cube root of 166375 by prime factorization method-45556575

Question

Toppr Admin · Accepted Answer

On prime factorising- we get-166375-5-xD7-5-xD7-5-xD7-11-xD7-11-xD7-11-xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -53-xD7-113-Then- cube root of 166375 is-3-x221A-166375-3-x221A-53-xD7-113-5-xD7-11-55-Therefore- option B is correct-

Find the cube root of $166375$ by prime factorization method.
$45$
$55$
$65$
$75$

On prime factorising, we get,
$166375 = 5 \times 5 \times 5 \times 11 \times 11 \times 11$
$= 5^{3} \times 11^{3}$ .

Then, cube root of $166375$ is:
$\sqrt[3]{166375} = \sqrt[3]{5^{3} \times 11^{3}} = 5 \times 11 = 55$ .

Therefore, option $B$ is correct.

Find the cube root of 166375 by prime factorization method.45556575

On prime factorising, we get,166375=5×5×5×11×11×11 =53×113.Then, cube root of 166375 is:3√166375=3√53×113=5×11=55.Therefore, option B is correct.

Find the cube root of $166375$ by prime factorization method.
$45$
$55$
$65$
$75$

On prime factorising, we get,
$166375 = 5 \times 5 \times 5 \times 11 \times 11 \times 11$
$= 5^{3} \times 11^{3}$ .

Then, cube root of $166375$ is:
$\sqrt[3]{166375} = \sqrt[3]{5^{3} \times 11^{3}} = 5 \times 11 = 55$ .

Therefore, option $B$ is correct.