Find the diagonal of a square whose side is 10 cm

Question

Toppr Admin · Accepted Answer

The side of square is 10-xA0-cmIn right angled -x25B3-ABDAB2-AD2-BD2 -according to Pythagoras theorem-10-2-10-2-BD2-100-100-BD2BD2-200BD-10-x221A-2cm-x2234- Diagonal of square -10-x221A-2cm-

Find the diagonal of a square whose side is $10 c m$

The side of square is $10 c m$
In right angled $△ A B D$
$A B^{2} + A D^{2} = B D^{2}$ [according to Pythagoras theorem]
$(10)^{2} + (10)^{2} = B D^{2}$ $
$100 + 100 = B D^{2}$
$B D^{2} = 200$
$B D = 10 \sqrt{2} c m$
$∴$ Diagonal of square $= 10 \sqrt{2} c m$ .

Find the diagonal of a square whose side is 10 cm

The side of square is 10 cmIn right angled △ABDAB2+AD2=BD2 [according to Pythagoras theorem](10)2+(10)2=BD2$100+100=BD2BD2=200BD=10√2cm∴ Diagonal of square =10√2cm.

Find the diagonal of a square whose side is $10 c m$

The side of square is $10 c m$
In right angled $△ A B D$
$A B^{2} + A D^{2} = B D^{2}$ [according to Pythagoras theorem]
$(10)^{2} + (10)^{2} = B D^{2}$ $
$100 + 100 = B D^{2}$
$B D^{2} = 200$
$B D = 10 \sqrt{2} c m$
$∴$ Diagonal of square $= 10 \sqrt{2} c m$ .