Find the difference-dfrac-5-6-dfrac-4-9-

Question

Toppr Admin · Accepted Answer

It is known that -dfrac-a-b-dfrac-c-d-dfrac-a-times d-b-times c-b-times d-Thus-dfrac-5-6-dfrac-4-9-dfrac-5-times 9-4-times 6-6-times 9-160- -160- -160- -160- -160- -160- -dfrac-45-24-54-160- -160- -160- -160- -160- -160- -160-dfrac-7-18-

Find the difference:
$$\dfrac{5}{6}-\dfrac{4}{9}$$

It is known that $$\dfrac{a}{b}-\dfrac{c}{d}=\dfrac{(a\times d)-(b\times c)}{b\times d}$$

Thus,
$$\dfrac{5}{6}-\dfrac{4}{9}=\dfrac{(5\times 9)-(4\times 6)}{6\times 9}$$

$$=\dfrac{45-24}{54}$$

$$=\dfrac{7}{18}$$

Find the difference:$$\dfrac{5}{6}-\dfrac{4}{9}$$

It is known that $$\dfrac{a}{b}-\dfrac{c}{d}=\dfrac{(a\times d)-(b\times c)}{b\times d}$$Thus,$$\dfrac{5}{6}-\dfrac{4}{9}=\dfrac{(5\times 9)-(4\times 6)}{6\times 9}$$ $$=\dfrac{45-24}{54}$$ $$=\dfrac{7}{18}$$

Find the difference:
$$\dfrac{5}{6}-\dfrac{4}{9}$$

It is known that $$\dfrac{a}{b}-\dfrac{c}{d}=\dfrac{(a\times d)-(b\times c)}{b\times d}$$

Thus,
$$\dfrac{5}{6}-\dfrac{4}{9}=\dfrac{(5\times 9)-(4\times 6)}{6\times 9}$$

$$=\dfrac{45-24}{54}$$

$$=\dfrac{7}{18}$$