Find the distance of the point (−1,1) from the line 12(x+6)=5(y−2)
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Solution
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The given equation of the line is 12(x+6)=5(y−2) ⇒12x+72=5y−10 ⇒12x−5y+82=0 Therefore, the distance of point (−1,1) from the given line =|12(−1)+(−5)(1)+82|√(12)2+(−5)2 units =|−12−5+82|√169 units =|65|13 units =5 units
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