Find the domain and range of the real f defined by f-x- - displaystyle left - x-1 right -

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Toppr Admin · Accepted Answer

The given real function is f-x-x-x2212-1-It is clear that-xA0-x-x2212-1- is defined for all real numbers-x2234- Domain of f-RThus for-xA0-x-x2208-R-x-x2212-1- assumes all non-negative real numbers-Hence the range of f is the set of all non-negative real numbers-0-x221E-

Find the domain and range of the real function $f$ defined by $f (x) = | x - 1 |$

The given real function is $f (x) = | x - 1 |$
It is clear that $| x - 1 |$ is defined for all real numbers
$∴$ Domain of $f = R$
Thus for $x \in R, | x - 1 |$ assumes all non-negative real numbers.
Hence the range of f is the set of all non-negative real numbers= $(0, \infty)$

Find the domain and range of the real function f defined by f(x)=|x−1|

The given real function is f(x)=|x−1|It is clear that |x−1| is defined for all real numbers∴ Domain of f=RThus for x∈R,|x−1| assumes all non-negative real numbers.Hence the range of f is the set of all non-negative real numbers=(0,∞)

Find the domain and range of the real function $f$ defined by $f (x) = | x - 1 |$

The given real function is $f (x) = | x - 1 |$
It is clear that $| x - 1 |$ is defined for all real numbers
$∴$ Domain of $f = R$
Thus for $x \in R, | x - 1 |$ assumes all non-negative real numbers.
Hence the range of f is the set of all non-negative real numbers= $(0, \infty)$