Find the equation of centre -1- 1- and radius sqrt-2-

Question

Toppr Admin · Accepted Answer

Centre -1-1- -p-a-radius -x221A-2-r-xA0-x-x2212-p-2-y-x2212-q-2-r2-x21D2-x-x2212-1-2-y-x2212-1-2-x221A-2-2-xA0-x21D2-x2-1-2x-y2-1-2y-2-xA0-x21D2-x2-y2-2x-2y-0

Find the equation of centre $(1, 1)$ and radius $\sqrt{2}$ .

centre (1,1) (p,a)
radius $\sqrt{2}$ =r
$(x - p)^{2} + (y - q)^{2} = r^{2}$
$\Rightarrow (x - 1)^{2} + (y - 1)^{2} = (\sqrt{2})^{2}$
$\Rightarrow x^{2} + 1 + 2 x + y^{2} + 1 + 2 y = 2$
$\Rightarrow x^{2} + y^{2} + 2 x + 2 y = 0$

Find the equation of centre (1,1) and radius √2.

centre (1,1) (p,a)radius √2=r (x−p)2+(y−q)2=r2⇒(x−1)2+(y−1)2=(√2)2 ⇒x2+1+2x+y2+1+2y=2 ⇒x2+y2+2x+2y=0

Find the equation of centre $(1, 1)$ and radius $\sqrt{2}$ .

centre (1,1) (p,a)
radius $\sqrt{2}$ =r
$(x - p)^{2} + (y - q)^{2} = r^{2}$
$\Rightarrow (x - 1)^{2} + (y - 1)^{2} = (\sqrt{2})^{2}$
$\Rightarrow x^{2} + 1 + 2 x + y^{2} + 1 + 2 y = 2$
$\Rightarrow x^{2} + y^{2} + 2 x + 2 y = 0$