Find the equation of parabola whose focus is the point $(- 6, - 6)$ and vertex is at $(- 2, 2) .$
${(2 x - y)}^{2} + 104 x + 148 y - 124 = 0$
${(2 x - y)}^{2} + 52 x + 74 y - 62 = 0$
${(x - 2 y)}^{2} - 104 x - 148 y - 124 = 0$
${(x - y)}^{2} + 52 x + 74 y - 62 = 0$

Question

Toppr Admin · Accepted Answer

Given focus S-x2212-6-x2212-6- and vertex A-x2212-2-2-Slope of SA -x2212-6-x2212-2-x2212-6-2-2

Find the equation of parabola whose focus is the point (−6,−6) and vertex is at (−2,2).(2x−y)2+104x+148y−124=0(2x−y)2+52x+74y−62=0(x−2y)2−104x−148y−124=0(x−y)2+52x+74y−62=0