Find the equation of the circle with centre -2- 3- and radius 4

Question

Toppr Admin · Accepted Answer

Here it is given that centre -h-k-x2212-2-3- and radius r-4Therefore the equation of the circle is-x-2-2-y-x2212-3-2-4-2-x21D2-x2-4x-4-y2-x2212-6y-9-16-x21D2-x2-y2-4x-x2212-6y-x2212-3-0

Find the equation of the circle with centre $(- 2, 3)$ and radius $4$

Here it is given that centre $(h, k) = (- 2, 3)$ and radius $r = 4$
Therefore the equation of the circle is
$(x + 2)^{2} + (y - 3)^{2} = (4)^{2}$
$\Rightarrow x^{2} + 4 x + 4 + y^{2} - 6 y + 9 = 16$
$\Rightarrow x^{2} + y^{2} + 4 x - 6 y - 3 = 0$

Find the equation of the circle with centre (−2,3) and radius 4

Here it is given that centre (h,k)=(−2,3) and radius r=4Therefore the equation of the circle is(x+2)2+(y−3)2=(4)2⇒x2+4x+4+y2−6y+9=16⇒x2+y2+4x−6y−3=0

Find the equation of the circle with centre $(- 2, 3)$ and radius $4$

Here it is given that centre $(h, k) = (- 2, 3)$ and radius $r = 4$
Therefore the equation of the circle is
$(x + 2)^{2} + (y - 3)^{2} = (4)^{2}$
$\Rightarrow x^{2} + 4 x + 4 + y^{2} - 6 y + 9 = 16$
$\Rightarrow x^{2} + y^{2} + 4 x - 6 y - 3 = 0$