Find the equation of the circle with centre (12,14) and radius 112
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Solution
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Here it is given that centre (h,k)=(12,14) and radius r=12 Therefore the equation of the circle is (x−12)2+(y−14)2=(112)2 ⇒x2−x+14+y2−y2+116=1144 ⇒x2−x+14+y2−y2+116−1144=0 ⇒144x2−144x+36+144y2−72y+9−1=0 ⇒36x2+36y2−36x−18y+11=0
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