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Question

Find the expansion (3x22ax+3a2)3 using binomial theorem.

Solution
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For binomial expansion first let's do a small pairing inside the bracket
[3x2a(2x3a)]3
Now let's expand this as be normally do for two digit expansion.

[3x2a(2x3a)]3=(3x2)33C1(3x2)2.a(2x3a)+3C2(3x2).a2(2x3a)2a3(2x3a)3
27x654x5a+81a2x4108a3x3+81a4x38a3x3+36a4x254a5x+27a6
27x654x5a+117a2x4116a3x3+117a4x354a5x+27a6

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