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Standard X
Mathematics
Question
Find the expansion of
(
x
+
1
)
(
x
+
4
)
(
x
+
7
)
x
3
+
12
x
2
−
39
x
+
28
x
3
+
12
x
2
+
39
x
+
28
x
3
−
12
x
2
+
39
x
+
28
None of these
A
None of these
B
x
3
+
12
x
2
−
39
x
+
28
C
x
3
−
12
x
2
+
39
x
+
28
D
x
3
+
12
x
2
+
39
x
+
28
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Solution
Verified by Toppr
(
x
+
1
)
(
x
+
4
)
(
x
+
7
)
=
(
x
2
+
4
x
+
x
+
4
)
(
x
+
7
)
=
(
x
2
+
5
x
+
4
)
(
x
+
7
)
=
x
3
+
7
x
2
+
5
x
2
+
35
x
+
4
x
+
28
=
x
3
+
12
x
2
+
39
x
+
28
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