0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

Find the first three terms in the expansion of :
1(1+x)21+4x

Solution
Verified by Toppr

(1+x)n=1+nx+(n)(n1)x22!+......(n!)xnn!

Where n is negative or fraction


let
y=(1+x)2(1+4x)12
=(12x+6.x22!........)(12x+34.16x22!..........)
=14x+13x2.......

Was this answer helpful?
0
Similar Questions
Q1
Find the first three terms in the expansion of :
1(1+x)21+4x
View Solution
Q2
Find the first three terms in the expansion of :
(1+x)34+1+5x(1x)2
View Solution
Q3
Find the first three terms in the expansion of (1+3x)12(12x)13
View Solution
Q4

In the expansion of (1+ax)n, the first three terms are 1+12x+64x2, then n=


View Solution
Q5
If the first three terms in the expansion of (1+ax)n in ascending powers of x are 1+12x+64x2, find n and a.
View Solution