Find the inclination of the line whose slope is displaystyle frac-1-sqrt3-

Question

Toppr Admin · Accepted Answer

Slope of a line m-tan-x3B8- where -x3B8- is the inclination of the line with the x - axis- -xA0-Given slope -1-x221A-3tan-x3B8-1-x221A-3We know that tan300-1-x221A-3-gt-x3B8-300 Inclination-xA0- -300

Find the inclination of the line whose slope is $\frac{1}{\sqrt{3}}$

Slope of a line $m = tan θ$ , where $θ$ is the inclination of the line with the x - axis.
Given slope $= \frac{1}{\sqrt{3}}$
$tan θ = \frac{1}{\sqrt{3}}$
We know that $t a n 30^{0} = \frac{1}{\sqrt{3}}$
$=> θ = 30^{0}$
Inclination $= 30^{0}$

Find the inclination of the line whose slope is 1√3

Slope of a line m=tanθ, where θ is the inclination of the line with the x - axis. Given slope =1√3tanθ=1√3We know that tan300=1√3=>θ=300 Inclination =300

Find the inclination of the line whose slope is $\frac{1}{\sqrt{3}}$

Slope of a line $m = tan θ$ , where $θ$ is the inclination of the line with the x - axis.
Given slope $= \frac{1}{\sqrt{3}}$
$tan θ = \frac{1}{\sqrt{3}}$
We know that $t a n 30^{0} = \frac{1}{\sqrt{3}}$
$=> θ = 30^{0}$
Inclination $= 30^{0}$