Find the inclination of the line whose slope is sqrt3

Question

Toppr Admin · Accepted Answer

Slope of a line m-tan-x3B8- where -x3B8- is the inclination of the line with the x - axis- -xA0-Given slope -x221A-3tan-x3B8-x221A-3We know that tan600-x221A-3-gt-x3B8-600 Inclination-xA0- -600

Find the inclination of the line whose slope is $\sqrt{3}$

Slope of a line $m = tan θ$ , where $θ$ is the inclination of the line with the x - axis.
Given slope $= \sqrt{3}$
$tan θ = \sqrt{3}$
We know that $tan 60^{0} = \sqrt{3}$
$=> θ = 60^{0}$
Inclination $= 60^{0}$

Find the inclination of the line whose slope is √3

Slope of a line m=tanθ, where θ is the inclination of the line with the x - axis. Given slope =√3tanθ=√3We know that tan600=√3=>θ=600 Inclination =600

Find the inclination of the line whose slope is $\sqrt{3}$

Slope of a line $m = tan θ$ , where $θ$ is the inclination of the line with the x - axis.
Given slope $= \sqrt{3}$
$tan θ = \sqrt{3}$
We know that $tan 60^{0} = \sqrt{3}$
$=> θ = 60^{0}$
Inclination $= 60^{0}$