Find the largest three-digit number which is exactly divisible by 47-

Question

Toppr Admin · Accepted Answer

Smallest 5 digit number- - 10000-On dividing -10000- by -254- we getRemainder - 94So -254 - 94 - 160- should be added to -10000- to get the smallest 5 digit number divisible by -254-therefore 10000 - 160 - 10160-

Find the largest three-digit number which is exactly divisible by $$47.$$

smallest 5 digit number$$ = 10000$$
On dividing $$10000$$ by $$254,$$ we get
Remainder = 94
So $$254 - 94 = 160$$ should be added to $$10000$$ to get the smallest 5 digit number divisible by $$254.$$
$$\therefore 10000 + 160 = 10160$$

Find the largest three-digit number which is exactly divisible by $$47.$$

smallest 5 digit number$$ = 10000$$On dividing $$10000$$ by $$254,$$ we getRemainder = 94So $$254 - 94 = 160$$ should be added to $$10000$$ to get the smallest 5 digit number divisible by $$254.$$$$\therefore 10000 + 160 = 10160$$

smallest 5 digit number$$ = 10000$$
On dividing $$10000$$ by $$254,$$ we get
Remainder = 94
So $$254 - 94 = 160$$ should be added to $$10000$$ to get the smallest 5 digit number divisible by $$254.$$
$$\therefore 10000 + 160 = 10160$$