Question

Find the least number of square tiles required to pave the ceiling of a room $15m,17cm$ long and $9m,2cm$ broad.

• A. $656$
• B. $814$
• C. $902$
• D. $738$

Answer 1

Answer: (B)

Given, length $=15m17cm=1517cm$

and width $=9m2cm=902cm$

Area of ceiling $=(1517\times 902)$

$or,A_{ceiling}=1368335c{m}^2$.

The dimension of square tile required to pave the ceiling $=$HCF of $\{1517,902\}=41$

Area of tile $=1681c{m}^2$

Number of square tile required $=\frac{A_{ceiling}}{Aonetile}=\left(\frac{1368334}{1681}\right)=$ $814$