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# Find the mean deviation about the mean for the data 38,70,48,40,42,55,63,46,54,44

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#### The given data is 38,70,48,40,42,55,63,46,54,44Mean ¯x=38+70+48+40+42+55+63+46+54+4410 =50010=50The deviations of the respective observation from the mean ¯x, i.e. xi=¯x are −12,20,−2,−10,−8,5,13,−4,4,−6.The absolute values of the deviations i.e.∣x1−¯x∣ are 12,20,2,10,8,5,13,4,4,6The required mean deviation about the mean is M.D.=∑10i=1∣xi−¯x∣10 =12+10+2+10+8+5+13+4+4+610 =8410 =8.4

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