$$\textbf{Part 1: Find the missing number in the first two ratios}$$
Consider first two ratios
Let the missing number be x
$$\dfrac{x}{45}=\dfrac{16}{40}$$
By cross multiplying, we get
$$\begin{aligned}&16 \times 45=x \times 40 \\&x=\frac{16 \times 45}{40}=18 \\&\therefore \frac{18}{45}=\frac{16}{40}\end{aligned}$$
$$\textbf{Part 2: Find the missing number in the last two ratios}$$
Consider last two ratios
Let the missing number be y
$$\frac{16}{40}=\frac{24}{y}$$
By cross multiplying, we get
$$\begin{aligned}&40 \times 24=y \times 16 \\&y=\frac{40 \times 24}{16}=60 \\&\therefore \frac{16}{40}=\frac{24}{60}\end{aligned}$$
$$\therefore \textbf{Missing numbers in the given ratio are 18 and 60}$$