Find the moment of inertia of thin uniform circular disc of mass 10 kg and radius 50 cm about its tangent
(A) in its plane
(B) perpendicular to its plane

Question

Find the moment of inertia of thin uniform circular disc of mass 10 kg and radius 50 cm about its tangent-A- in its plane -B- perpendicular to its plane

Toppr Admin · Accepted Answer

- - I - I-cm- - mR-2 -160- - - -dfrac -mR-2- -2- - mR-2 - -dfrac -3mR-2- -2- -160- - - -dfrac -3-2- -times 10 -times -dfrac -1-2-2 -160-160- - - -dfrac -15-4- kg-m-2 -160-

Find the moment of inertia of thin uniform circular disc of mass 10 kg and radius 50 cm about its tangent(A) in its plane (B) perpendicular to its plane

$$ \\ I = I_{cm} + mR^2 $$ $$ \\ = \dfrac {mR^2} {2} + mR^2 = \dfrac {3mR^2} {2} $$ $$ \\ = \dfrac {3}{2} \times 10 \times (\dfrac {1}{2})^2 $$ $$ \\ = \dfrac {15}{4} kg/m^2 $$

Find the moment of inertia of thin uniform circular disc of mass 10 kg and radius 50 cm about its tangent
(A) in its plane
(B) perpendicular to its plane

$$ \\ I = I_{cm} + mR^2 $$
$$ \\ = \dfrac {mR^2} {2} + mR^2 = \dfrac {3mR^2} {2} $$
$$ \\ = \dfrac {3}{2} \times 10 \times (\dfrac {1}{2})^2 $$
$$ \\ = \dfrac {15}{4} kg/m^2 $$