Find the multiplicative inverse -reciprocal- of the following rational number-dfrac-0-3-

Question

Toppr Admin · Accepted Answer

Let the reciprocal be -x-Then- -dfrac03-times x-1-Rightarrow 0-times x-3-160- -160- -160-Cross multiplication-Rightarrow x-dfrac30-But- division by -0- is not defined-Hence- the reciprocal does not exist-

Find the multiplicative inverse (reciprocal) of the following rational number:
$$\dfrac{0}{3}$$

Let the reciprocal be $$x$$.

Then, $$\dfrac03\times x=1$$
$$\Rightarrow 0\times x=3$$ [Cross multiplication]
$$\Rightarrow x=\dfrac30$$

But, division by $$0$$ is not defined.
Hence, the reciprocal does not exist.

Find the multiplicative inverse (reciprocal) of the following rational number:$$\dfrac{0}{3}$$

Let the reciprocal be $$x$$.Then, $$\dfrac03\times x=1$$$$\Rightarrow 0\times x=3$$ [Cross multiplication]$$\Rightarrow x=\dfrac30$$But, division by $$0$$ is not defined.Hence, the reciprocal does not exist.

Find the multiplicative inverse (reciprocal) of the following rational number:
$$\dfrac{0}{3}$$

Let the reciprocal be $$x$$.

Then, $$\dfrac03\times x=1$$
$$\Rightarrow 0\times x=3$$ [Cross multiplication]
$$\Rightarrow x=\dfrac30$$

But, division by $$0$$ is not defined.
Hence, the reciprocal does not exist.