Find the nearest integer to the square root of 232-

Question

Toppr Admin · Accepted Answer

We know- 152-225 and 162-256Also we have- 225-lt-232-lt-256-x27F9-152-lt-232-lt-162Difference of 225 and 232 is 7 whereas difference of 256 and 232 is 24-So- the square root of 232 is nearest to 15-Hence- the answer is 15

Find the nearest integer to the square root of $232$ .

We know, $15^{2} = 225$ and $16^{2} = 256$
Also we have, $225 < 232 < 256$
$⟹ 15^{2} < 232 < 16^{2}$
Difference of $225$ and $232$ is $7$ whereas difference of $256$ and $232$ is $24$ .
So, the square root of $232$ is nearest to $15$ .
Hence, the answer is $15$

Find the nearest integer to the square root of 232.

We know, 152=225 and 162=256Also we have, 225<232<256 ⟹152<232<162Difference of 225 and 232 is 7 whereas difference of 256 and 232 is 24. So, the square root of 232 is nearest to 15.Hence, the answer is 15

Find the nearest integer to the square root of $232$ .

We know, $15^{2} = 225$ and $16^{2} = 256$
Also we have, $225 < 232 < 256$
$⟹ 15^{2} < 232 < 16^{2}$
Difference of $225$ and $232$ is $7$ whereas difference of $256$ and $232$ is $24$ .
So, the square root of $232$ is nearest to $15$ .
Hence, the answer is $15$