Question

Find the number of sides of a regular polygon whose each exterior angles has a measure of
$$ 72^{\circ} $$

Answer 1

Let us assume the number of sides of the regular polygon be $$ n $$,

Sum of all exterior angles is $$360^o$$.
$$\begin{aligned}\text { Then, } n =\dfrac{360^{\circ}}{ 72^{\circ}} \\n =5\end{aligned}$$
Therefore, the number of sides of a regular polygon is $$5$$