Find the oxidation number of Mn in -MnO-4- ion-

Question

Toppr Admin · Accepted Answer

Let oxidation number of Mn be x-We know that- Ox- no- of O-x2212-2-So- Ox- no- Mn- 4-Ox- no- O-x2212-1x-4-x2212-2-x2212-1or x-x2212-8-x2212-1or x-8-x2212-1-7The oxidation number of Mn in -MnO4-x2212- ion is -7-

Find the oxidation number of $M n$ in $[M n O_{4}]^{-}$ ion.

Let oxidation number of $M n$ be $x$ .
We know that, Ox. no. of $O = - 2$ .
So, Ox. no. $M n$ + 4(Ox. no. $O$ ) $= - 1$
$x + 4 (- 2) = - 1$
or $x - 8 = - 1$
or $x = + 8 - 1 = + 7$
The oxidation number of $M n$ in $[M n O_{4}]^{-}$ ion is $+ 7$ .

Find the oxidation number of Mn in [MnO4]− ion.

Let oxidation number of Mn be x.We know that, Ox. no. of O=−2.So, Ox. no. Mn+ 4(Ox. no. O)=−1x+4(−2)=−1or x−8=−1or x=+8−1=+7The oxidation number of Mn in [MnO4]− ion is +7.

Find the oxidation number of $M n$ in $[M n O_{4}]^{-}$ ion.

Let oxidation number of $M n$ be $x$ .
We know that, Ox. no. of $O = - 2$ .
So, Ox. no. $M n$ + 4(Ox. no. $O$ ) $= - 1$
$x + 4 (- 2) = - 1$
or $x - 8 = - 1$
or $x = + 8 - 1 = + 7$
The oxidation number of $M n$ in $[M n O_{4}]^{-}$ ion is $+ 7$ .