Find the product of the zeroes of $$-2x^{2} + kx + 6$$.
$$\textbf{Step I: Comparing with the standard quadratic equation and determining the Product of roots}$$
$$\text{Let } \alpha ,\beta \text{ be roots of quadratic equation }-2x^{2}+kx+6=0$$
$$\text{If } \alpha ,\beta \text{ are roots of quadratic equation }ax^{2}+bx+c=0 \text{ then }\alpha \cdot \beta =\dfrac{c}{a}$$
$$\Rightarrow \alpha \cdot \beta =\dfrac{6}{-2}$$
$$\Rightarrow \alpha \cdot \beta =-3$$
$$\textbf{Hence, the product of zeros of }\boldsymbol{-2x^{2}+kx+6=0}\textbf{ is -3.}$$