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Question

Find the reciprocal of the following:
$$\left(\dfrac{1}{2}\times \dfrac{1}{4}\right)+\left(\dfrac{1}{2}\times 6\right)$$

Solution
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$$\left(\dfrac{1}{4}\times \dfrac{1}{4}\right)+\left(\dfrac{1}{2}\times 6\right)$$
$$=\left(\dfrac{1}{4}\times \dfrac{1}{4}\right)+\left(\dfrac{1}{2}\times 6\right)$$
$$=\dfrac{1}{8}+\dfrac{6}{2}$$
$$=\dfrac{1+24}{8}$$
$$=\dfrac{25}{8}$$
Therefore, the reciprocal is $$\dfrac{8}{25}$$

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