Find the roots of 2x-2-x-4-0 by quadratic formula-

Question

Toppr Admin · Accepted Answer

2x2-x-x2212-4-0Compairing-xA0-with ax2-bx-c-0a - 2 b - 1 c - -4-x2234-x2212-b-xB1-x221A-b2-x2212-4ac2a-x2212-1-xB1-x221A-12-x2212-4-xD7-2-x2212-4-2-xD7-2-x2212-1-xB1-x221A-334-x2234-x-x2212-1-x221A-334 OR x-x2212-1-x2212-x221A-334

Find the roots of $2 x^{2} + x - 4 = 0$ by quadratic formula.

$2 x^{2} + x - 4 = 0$
Compairing with $a x^{2} + b x + c = 0$
a = 2 b = 1 c = -4
$∴ \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$
$= \frac{- 1 \pm \sqrt{1^{2} - 4 \times 2 (- 4)}}{2 \times 2}$
$\frac{- 1 \pm \sqrt{33}}{4}$
$∴ x = \frac{- 1 + \sqrt{33}}{4}$ OR $x = \frac{- 1 - \sqrt{33}}{4}$

Find the roots of 2x2+x−4=0 by quadratic formula.

2x2+x−4=0Compairing with ax2+bx+c=0a = 2 b = 1 c = -4∴−b±√b2−4ac2a=−1±√12−4×2(−4)2×2−1±√334∴x=−1+√334 OR x=−1−√334

Find the roots of $2 x^{2} + x - 4 = 0$ by quadratic formula.

$2 x^{2} + x - 4 = 0$
Compairing with $a x^{2} + b x + c = 0$
a = 2 b = 1 c = -4
$∴ \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$
$= \frac{- 1 \pm \sqrt{1^{2} - 4 \times 2 (- 4)}}{2 \times 2}$
$\frac{- 1 \pm \sqrt{33}}{4}$
$∴ x = \frac{- 1 + \sqrt{33}}{4}$ OR $x = \frac{- 1 - \sqrt{33}}{4}$