Find the slant height of a cone whose-Base radius -14-cm- height 0-48-mBase diameter -70-cm- curved surface area -4070-cm-252-cm-37-cm50-cm-37-cm51-cm-37-cm50-cm-36-cm

Question

Toppr Admin · Accepted Answer

Radius-14cm-height-0-48m-48cmslantheight2-radius2-height2l2-142-482-l2-2500-l-50cm

Find the slant height of a cone whose,
Base radius $= 14 c m$ , height $0.48 m$
Base diameter $= 70 c m$ , curved surface area $= 4070 c m^{2}$
$52 c m; 37 c m$
$50 c m; 37 c m$
$51 c m; 37 c m$
$50 c m; 36 c m$

$r a d i u s = 14 c m, h e i g h t = 0.48 m = 48 c m$
$s l a n t h e i g h t^{2} = r a d i u s^{2} + h e i g h t^{2}$
$l^{2} = 14^{2} + 48^{2}, l^{2} = 2500, l = 50 c m$

Find the slant height of a cone whose,Base radius =14cm, height 0.48mBase diameter =70cm, curved surface area =4070cm252cm;37cm50cm;37cm51cm;37cm50cm;36cm

radius=14cm,height=0.48m=48cmslantheight2=radius2+height2l2=142+482,l2=2500,l=50cm

Find the slant height of a cone whose,
Base radius $= 14 c m$ , height $0.48 m$
Base diameter $= 70 c m$ , curved surface area $= 4070 c m^{2}$
$52 c m; 37 c m$
$50 c m; 37 c m$
$51 c m; 37 c m$
$50 c m; 36 c m$

$r a d i u s = 14 c m, h e i g h t = 0.48 m = 48 c m$
$s l a n t h e i g h t^{2} = r a d i u s^{2} + h e i g h t^{2}$
$l^{2} = 14^{2} + 48^{2}, l^{2} = 2500, l = 50 c m$