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Standard VIII
Mathematics
Question
Find the square of:
3
a
−
4
b
.
a
2
+
4
a
b
+
b
2
9
a
2
−
24
a
b
+
16
b
2
9
a
2
−
a
b
+
16
b
2
9
a
2
+
24
a
b
+
b
2
A
a
2
+
4
a
b
+
b
2
B
9
a
2
+
24
a
b
+
b
2
C
9
a
2
−
24
a
b
+
16
b
2
D
9
a
2
−
a
b
+
16
b
2
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Solution
Verified by Toppr
Given,
(
3
a
−
4
b
)
.
On squaring, we get,
(
3
a
−
4
b
)
2
.
We know,
(
x
+
y
)
2
=
x
2
+
y
2
+
2
x
y
.
Then,
(
3
a
−
4
b
)
2
=
(
3
a
)
2
−
2
(
3
a
)
(
4
b
)
+
(
4
b
)
2
=
9
a
2
−
24
a
b
+
16
b
2
.
Therefore, option
B
is correct.
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