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Question

Find the squares of the following numbers without actual multiplication:
49, 52
  1. 2441;2704
  2. 2401;2784
  3. 2401;2704
  4. 2441;2784

A
2401;2704
B
2401;2784
C
2441;2784
D
2441;2704
Solution
Verified by Toppr

492=(40+9)2=40(40+9)+9(40+9)
=(40)2+40×9+9×40+92
=1600+360+360+81
So, 492=2401
522=(50+2)2=50(50+2)+2(50+2)
=502+50×2+2×50+22
=2500+100+100+4
So, 522=2704.

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