Find the squares of the following numbers without actual multiplication: 49, 52
2441;2704
2401;2784
2401;2704
2441;2784
A
2401;2704
B
2401;2784
C
2441;2784
D
2441;2704
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Solution
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492=(40+9)2=40(40+9)+9(40+9) =(40)2+40×9+9×40+92 =1600+360+360+81 So, 492=2401 522=(50+2)2=50(50+2)+2(50+2) =502+50×2+2×50+22 =2500+100+100+4 So, 522=2704.
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