Find the sum of 20 terms of the series 0.15,0.015,0.0015,...20
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Solution
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The given G.P. is 0.15,0.015,0.0015,... Here, a=0.15 and r=0.0150.15=0.1 ⇒Sn=a(1−rn)1−r∴S20=0.15[1−(0.1)20]1−0.1=0.150.9[1−(0.1)20]=1590[1−(0.1)20]=16[1−(0.1)20]
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