Find the of deviation of all observations of the data 5- 8- 10- 15- 22 from their mean-

Question

Toppr Admin · Accepted Answer

5- 8- 1- 15- 22Moon-xA0- -xA0-sum of observationNo- of obesuation-5-8-10-15-225-605-12Sum-of deviations-5-x2212-12-8-x2212-12-10-x2212-12-15-x2212-12-22-x2212-12-7-x2212-4-x2212-2-3-10-7-4-2-3-10-26

Find the sum of deviation of all observations of the data 5, 8, 10, 15, 22 from their mean.

5, 8, 1, 15, 22
$Moon = \frac{sum of observation}{No . of obesuation}$

$= \frac{5 + 8 + 10 + 15 + 22}{5}$

$= \frac{60}{5} = 12$
Sum of deviations
$= | 5 - 12 | + | 8 - 12 | + | 10 - 12 | + | 15 - 12 | + | 22 - 12 |$
$= | 7 | + | - 4 | + | - 2 | + | 3 | + | 10 |$
$= 7 + 4 + 2 + 3 + 10$
$= 26$

Find the sum of deviation of all observations of the data 5, 8, 10, 15, 22 from their mean.

5, 8, 1, 15, 22Moon = sum of observationNo. of obesuation=5+8+10+15+225=605=12Sum of deviations=|5−12|+|8−12|+|10−12|+|15−12|+|22−12|=|7|+|−4|+|−2|+|3|+|10|=7+4+2+3+10=26

5, 8, 1, 15, 22
$Moon = \frac{sum of observation}{No . of obesuation}$

$= \frac{5 + 8 + 10 + 15 + 22}{5}$

$= \frac{60}{5} = 12$
Sum of deviations
$= | 5 - 12 | + | 8 - 12 | + | 10 - 12 | + | 15 - 12 | + | 22 - 12 |$
$= | 7 | + | - 4 | + | - 2 | + | 3 | + | 10 |$
$= 7 + 4 + 2 + 3 + 10$
$= 26$