Find the of first n natural numbers-

Question

Toppr Admin · Accepted Answer

First n natural numbers are 1-2-3-4-n-x2212-1-n-Clearly- it is an A-P- with first term 1 and common difference 1-Let Sn denote the required- Then-Sn-n2-1-n-xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -Using-Sn-n2-a-l-x27F9-Sn-n-n-1-2

Find the sum of first $n$ natural numbers.

First $n$ natural numbers are $1, 2, 3, 4, . . ., (n - 1), n$ .

Clearly, it is an A.P. with first term $1$ and common difference $1$ .

Let $S_{n}$ denote the required. Then,
$S_{n} = \frac{n}{2} (1 + n)$ $[U s i n g : S_{n} = \frac{n}{2} (a + l)]$
$⟹ S_{n} = \frac{n (n + 1)}{2}$

Find the sum of first n natural numbers.

First n natural numbers are 1,2,3,4,...,(n−1),n.Clearly, it is an A.P. with first term 1 and common difference 1.Let Sn denote the required. Then,Sn=n2(1+n) [Using:Sn=n2(a+l)]⟹Sn=n(n+1)2

Find the sum of first $n$ natural numbers.

First $n$ natural numbers are $1, 2, 3, 4, . . ., (n - 1), n$ .

Clearly, it is an A.P. with first term $1$ and common difference $1$ .

Let $S_{n}$ denote the required. Then,
$S_{n} = \frac{n}{2} (1 + n)$ $[U s i n g : S_{n} = \frac{n}{2} (a + l)]$
$⟹ S_{n} = \frac{n (n + 1)}{2}$