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Standard IX
Mathematics
Question
Find the sum of the divisors of
18
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Solution
Verified by Toppr
Standard form of
18
is
2
1
×
3
2
σ
(
18
)
=
(
2
1
+
1
−
1
2
−
1
)
×
(
3
2
+
1
−
1
3
−
1
)
=
(
2
2
−
1
2
−
1
)
×
(
3
3
−
1
3
−
1
)
=
(
4
−
1
2
−
1
)
×
(
27
−
1
3
−
1
)
=
(
3
1
)
×
(
26
2
)
=
3
×
13
=
39
∴
Sum of divisors of
18
=
39
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