Question

Find the sum of
$$-312, \,39$$ and $$192$$

Answer 1

$$-312 + 39 + 192 $$

$$=[-312 + 39 ]+ 192 $$

Here we will $$1^{st}$$ solve square bracket

$$\therefore [-312+39]+192=-273+192$$

$$-81$$

$$-81$$ is the sum of $$-132, \,39$$ and $$192$$