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Standard XI
Mathematics
NCERT
Question
Find the sum to
n
terms of the given series whose
n
t
h
terms is given by
(
2
n
−
1
)
2
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Solution
Verified by Toppr
a
n
=
(
2
n
−
1
)
2
=
4
n
2
−
4
n
+
1
∴
S
n
=
∑
n
k
=
1
a
k
=
∑
n
k
=
1
(
4
k
2
−
4
k
+
1
)
=
4
∑
n
k
=
1
k
2
−
4
∑
n
k
=
1
k
+
∑
n
k
=
1
1
=
4
n
(
n
+
1
)
(
2
n
+
1
)
6
−
4
n
(
n
+
1
)
2
+
n
=
2
n
(
n
+
1
)
(
2
n
+
1
)
3
−
2
n
(
n
+
1
)
+
n
=
n
[
2
(
2
n
2
+
3
n
+
1
)
3
−
2
(
n
+
1
)
+
1
]
=
n
[
4
n
2
+
6
n
+
2
−
6
n
−
6
+
3
3
]
=
n
[
4
n
2
−
1
3
]
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Similar Questions
Q1
Find the sum to
n
terms of the given series whose
n
t
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terms is given by
(
2
n
−
1
)
2
View Solution
Q2
Find the sum to
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n
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